In February of 2007, Jeff Atwood wrote Why Can’t Programmers.. Program in which he devises the FizzBuzz test.

Write a program that prints the numbers from 1 to 100. But for multiples of three print “Fizz” instead of the number and for the multiples of five print “Buzz”. For numbers which are multiples of both three and five print “FizzBuzz”.

Regardless of how effective FizzBuzz tests may or may not be as indicators of long-term developer performance, it has inspired code golf implementations in almost every conceivable programming language.

A common approach to code golf solutions is predicated on the understanding that numbers which are multiples of both three and five (as per the challenge) are also divisible by 15. So mod 15 is a great way to infer if a number is divisible by both three, and five and meets part of the requirements.

I enjoy code golf solutions that are concise, and demonstrate thorough understanding of the problem. However, while mod 15 is an elegant solution, I’d argue that using mod 15 as a shortcut to understand if a number is divisible by three wouldn’t necessarily be obvious to readers without supporting comments.

At the risk of missing the point of code golf, I feel brevity for brevities sake and loss of comprehension vs. the spec is something to avoid at all costs. So for my code golf solution to FizzBuzz, I’m inclined to preserve (the slightly) longer version that which mod 15.

With that in mind, here’s my FizzBuzz solution formatted for readability, and leaning on LINQ, string interpolation and the inline if feature of C#.

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foreach (var n in Enumerable.Range(1, 100).Select(i =>
    i % 3 == 0 && i % 5 == 0 ? "FizzBuzz"
        : i % 3 == 0 ? "Fizz"
            : i % 5 == 0 ? "Buzz"
                : $"{i}"))
{
    Console.WriteLine(n);
}

After formatting and extraneous spaces are removed, the same code, golfed onto a single line weighs in at 137 characters:

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foreach(var n in Enumerable.Range(1, 100).Select(i=>i%3==0&&i%5==0?"FizzBuzz":i%3==0?"Fizz":i%5==0?"Buzz":$"{i}")){Console.WriteLine(n);}